2012
DOI: 10.1007/s11565-012-0153-9
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A scale-invariant Klein–Gordon model with time-dependent potential

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Cited by 22 publications
(32 citation statements)
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“…In this paper we prove results in the following cases: (1)The case δ0. In this case the mass term is predominant and not non‐effective in the sense of . (2)The case δ(n+1)2. In this case the dissipation term is predominant and not non‐effective in the sense of . (3)The case δ=1.…”
Section: Resultsmentioning
confidence: 63%
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“…In this paper we prove results in the following cases: (1)The case δ0. In this case the mass term is predominant and not non‐effective in the sense of . (2)The case δ(n+1)2. In this case the dissipation term is predominant and not non‐effective in the sense of . (3)The case δ=1.…”
Section: Resultsmentioning
confidence: 63%
“…To reach this goal we will proceed the following strategy: (1)If δ0, in other words, if the mass is predominant and not non‐effective , then after the dissipative change of variables vfalse(t,xfalse)=(1+t)μ12wfalse(t,xfalse)the Cauchy problem becomes trueleftwttnormalΔw+μ(1+t)2w=0,leftw(s,x)=false(1+sfalse)μ12v0(x),1emwt(s,x)=false(1+sfalse)μ12v1(x)+0falseμ12false(1+sfalse)μ121v0(x),where μ=μ12μ124+μ22. Note that δ=14μ0 if, and only if, μ14, i.e., we are dealing with not non‐effective masses and we can use special function theory to derive estimates for solutions to this Cauchy problem, as it was done in a special case in . (2)If δ(n+1)2, i.e., if the dissipation is predominant and not non‐effective , then after the change of variables …”
Section: Philosophy Of Our Approachmentioning
confidence: 99%
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“…for some C ϵ > 0, where u(t, x) is the solution to the Cauchy problem (14) with initial data (u 0 , u 1 ) ∈ F ϵ , and v(t, x) is the solution to the Cauchy problem (23) with initial data (v 0 , v 1 ) = W ϵ + (u 0 , u 1 ).…”
Section: Corollarymentioning
confidence: 99%