“…Examples of test elements of free Lie algebras of rank two were given by Mikhalev and Yu [10]. Other examples of test elements were considered by Mikhalev, Umirbaev and Yu [11], Temizyurek and Ekici [13] and Esmerligil [2].…”
Section: Introductionmentioning
confidence: 99%
“…It turns out that the test rank of a free polynilpotent Lie algebra is either equal to the rank of the Lie algebra or is one less than the rank of it. Interest in the test ranks of free soluble Lie algebras is explained in [13] and [15]. Temizyurek and Ekici [13] showed that a free soluble Lie algebra of rank 2 with solvability class 3 has test rank 1 and pointed out the particular test element for such algebras.…”
Section: Introductionmentioning
confidence: 99%
“…Interest in the test ranks of free soluble Lie algebras is explained in [13] and [15]. Temizyurek and Ekici [13] showed that a free soluble Lie algebra of rank 2 with solvability class 3 has test rank 1 and pointed out the particular test element for such algebras. The test rank for free soluble Lie algebras of solvability class greater than 3 is calculated by Timoshenko and Shevelin in [15] and it is shown that the test rank of a free soluble Lie algebra of rank n ≥ 2 is equal to n − 1.…”
Let F be a free Lie algebra of rank n ≥ 2 and A be a free abelian Lie algebra of rank m ≥ 2. We prove that the test rank of the abelian product F ×A is m. Morever we compute the test rank of the algebra F/γ k (F) .
“…Examples of test elements of free Lie algebras of rank two were given by Mikhalev and Yu [10]. Other examples of test elements were considered by Mikhalev, Umirbaev and Yu [11], Temizyurek and Ekici [13] and Esmerligil [2].…”
Section: Introductionmentioning
confidence: 99%
“…It turns out that the test rank of a free polynilpotent Lie algebra is either equal to the rank of the Lie algebra or is one less than the rank of it. Interest in the test ranks of free soluble Lie algebras is explained in [13] and [15]. Temizyurek and Ekici [13] showed that a free soluble Lie algebra of rank 2 with solvability class 3 has test rank 1 and pointed out the particular test element for such algebras.…”
Section: Introductionmentioning
confidence: 99%
“…Interest in the test ranks of free soluble Lie algebras is explained in [13] and [15]. Temizyurek and Ekici [13] showed that a free soluble Lie algebra of rank 2 with solvability class 3 has test rank 1 and pointed out the particular test element for such algebras. The test rank for free soluble Lie algebras of solvability class greater than 3 is calculated by Timoshenko and Shevelin in [15] and it is shown that the test rank of a free soluble Lie algebra of rank n ≥ 2 is equal to n − 1.…”
Let F be a free Lie algebra of rank n ≥ 2 and A be a free abelian Lie algebra of rank m ≥ 2. We prove that the test rank of the abelian product F ×A is m. Morever we compute the test rank of the algebra F/γ k (F) .
Let F be a free Lie algebra of rank n ≥ 2 and R be a fully invariant ideal of F. We show that the test rank of the Lie algebra F/[R′, F] is equal to 1 when n is even and less than or equal to 2 when n is odd.
Let [Formula: see text] be the [Formula: see text]th solvable product of free abelian Lie algebras of finite rank. We prove that the test rank of [Formula: see text] is one less than the number of the factors. We also give a test set for endomorphisms of [Formula: see text].
scite is a Brooklyn-based organization that helps researchers better discover and understand research articles through Smart Citations–citations that display the context of the citation and describe whether the article provides supporting or contrasting evidence. scite is used by students and researchers from around the world and is funded in part by the National Science Foundation and the National Institute on Drug Abuse of the National Institutes of Health.