1980
DOI: 10.1007/bf02572690
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A partially ordered space which is not a priestley space

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Cited by 25 publications
(16 citation statements)
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“…This is not the case for every choice of M ∼ . A classic example of Stralka [40] shows that the ordered space M ∼ = {0, 1}; ≤, T , which generates the category of Priestley spaces, is not standard.…”
Section: Background Motivation and Overview Of Resultsmentioning
confidence: 99%
“…This is not the case for every choice of M ∼ . A classic example of Stralka [40] shows that the ordered space M ∼ = {0, 1}; ≤, T , which generates the category of Priestley spaces, is not standard.…”
Section: Background Motivation and Overview Of Resultsmentioning
confidence: 99%
“…If R satisfies the Priestley separation axiom, then we call R a Priestley quasi-order. Each Priestley quasi-order is closed, but the converse is not true in general [10,30]. A quasiordered Priestley space is a pair (X, R), where X is a Stone space and R is a Priestley quasi-order on X.…”
Section: Lattice Subordinations and The Priestley Separation Axiommentioning
confidence: 99%
“…Indeed, Stralka's well-known example (which we discuss further in Sect. 5.3) shows that the class of Priestley spaces (which is the Boolean core P BC of the class of ordered sets P) is not equal to the class of Boolean topological ordered sets [14]. Thus P is not standard.…”
Section: Relational Structuresmentioning
confidence: 99%