1989
DOI: 10.1017/s0017089500007692
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A note on the positive Schur property

Abstract: The purpose of this note is to characterize those Banach lattices (£, ||-||) which have the property: an operator T: E-> c 0 is a Dunford-Pettis operator if and only if T is regular (*) (i.e., T is the difference of two positive operators). Our characterization generalizes a theorem recently proved by Holub [6] The proof of our Theorem will be preceded by some lemmas. LEMMA 1. Let (E, ||||) denote a a-Dedekind complete Banach lattice. The following statements are equivalent: (i) Every Dunford-Pettis operator… Show more

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Cited by 27 publications
(22 citation statements)
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“…Tite erder continuity of the norm imphies tite follewing fact (see [15] Lemma 1): even' Dunferd-Pettis operator T-E--*c, is a difference of twe pesitive eperaters. TI-¡erefere even' continuous linear operater from E into 4 is regular, and so E itas te be discrete ( [14]).…”
Section: ¡9mentioning
confidence: 95%
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“…Tite erder continuity of the norm imphies tite follewing fact (see [15] Lemma 1): even' Dunferd-Pettis operator T-E--*c, is a difference of twe pesitive eperaters. TI-¡erefere even' continuous linear operater from E into 4 is regular, and so E itas te be discrete ( [14]).…”
Section: ¡9mentioning
confidence: 95%
“…Besides tite Seitur property ene can censider a weaker preperty called tite pesitive Scitur property ( [15]), i.e., 0-cx -*0 weakly implies x,,-*0 in nerm. A simple example ofa Banacit ¡attice witit tite positive Scitur property and wititout tite Scitur preperty is a space L'(ji), witere pi is net purely atemic.…”
Section: Remárks On Banách Lattices Witii the Positive Schur Propertymentioning
confidence: 99%
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“…For example, the Banach lattice L 1 ([0, 1]) has the positive Schur property but does not have the Schur property. For more information about this notion see [6].…”
Section: And Hence T (Bmentioning
confidence: 99%
“…In fact, it follows from Josefson-Nissenzweig theorem [9,11] that the existence of a sequence (x n ) of the topological dual of c such that x n = 1 for all n and x n −→ 0 for the weak topology σ (c , c). We consider the operator T, which we can find in Wnuk ( [15], p. 170), defined by…”
Section: Lemma 24 There Exists An Operator From C Into C 0 That Is mentioning
confidence: 99%