1977
DOI: 10.7146/math.scand.a-11725
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A note on dual Banach spaces.

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Cited by 19 publications
(15 citation statements)
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“…Conversely, if M is dually complete, it is a dual space and the predual is a certain completion of A (see e.g. (21)). Furthermore M' = E A (M)' is a Banach algebra, and there exists a natural homomorphism of A into M'.…”
Section: \(Tr a (A P ®A' P )A}\ = \{A' P A-a P )\ = \(A P -A' P A)\mentioning
confidence: 99%
“…Conversely, if M is dually complete, it is a dual space and the predual is a certain completion of A (see e.g. (21)). Furthermore M' = E A (M)' is a Banach algebra, and there exists a natural homomorphism of A into M'.…”
Section: \(Tr a (A P ®A' P )A}\ = \{A' P A-a P )\ = \(A P -A' P A)\mentioning
confidence: 99%
“…Proof Kaijser proved in [15], that a Banach space Y is a dual space if there is a set of continuous linear functionals E on Y that separates the points of Y and the closed unit ball of Y is compact in the weak topology generated by E.…”
Section: Theorem 23mentioning
confidence: 99%
“…Using the matrix expressions of , a, and b, a direct computation shows that equation (42) poses no constraints on the factor A 2 in the matrix expression of a, or, equivalenty, we have that…”
Section: Positive Trace-class Operatorsmentioning
confidence: 99%
“…which is equivalent to the previous equation. Then, if we fix k ∈ [1, ..., dim(H ⊥ ) and take b = |f k f l |, we immediately see that equation (42) poses no constraints on a. Putted differently, if a is in g , then the factor A 4 in the matrix expression of a is arbitrary. Next, in order to characterize the matrix elements of a ∈ g with respect to the basis elements in the subspace H , we need to exploit the arbitrariness of b in equation (42) "twice": we first have to consider b = x e kl |e k e l | (for all k, l ∈ [1, ..., dim(H )]), and then we have to consider b = y e kl |e k e l | (for all k, l ∈ [1, ..., dim(H )]).…”
Section: Positive Trace-class Operatorsmentioning
confidence: 99%