In a recent paper (see [2]), Orrin Frink introduced a method to provide Hausdorff compactifications for Tychonoff or completely regular 7\ spaces X. His method utilized the notion of a normal base. A normal base 2£ for the closed sets of a space X is a base which is a disjunctive ring of sets, disjoint members of which may be separated by disjoint complements of members of 2£'.Frink showed that if X has a normal base, then the Wallman space, (a{21£), consisting of the i^-ultrafilters is a Hausdorff compactification of X. This also showed that X must be a Tychonoff space. In this note we use the notion of ^-ultrafilters in a countably productive normal base 2£ to introduce a new space rj(^) consisting of all those iF-ultrafilters with the countable intersection property.Every normal base 3£ of X corresponds to a normal base 2£* in r]{2£) (and also in co(2?)). We show that every collection of J?*-ultrafilters with the countable intersection property is fixed, that is the intersection of all the members of the collection is non empty. In light of this fact, we say that r\{2?) is 3£*-real-compact. We also show that r)(^) is contained in thê -closure of X in ay(2£). Finally if 2£ is the collection of all zero-sets then r\{2£) is precisely the Hewitt real compactification of X. We have attempted to show that every realcompactification Y of a space X can be obtained as a space rj(^). This remains an open question.Many examples exist of normal bases which are countably productive. One of the most important is the collection of all zero-sets of a completely regular T 1 space. Gillman and Jerison in [3] have shown that this family is countably productive and also that it satisfies the requirements for a normal base. Thus every Tychonoff space has a countably productive normal base. DEFINITIONS. A base $£ for the closed sets of a T 1 space X is said to be disjunctive if given any closed set F and any point x not in F there is a closed set A of 2£ that contains x and is disjoint from F. The base is said to be normal if any two disjoint members A and B of 3£ are subsets respectively of disjoint complements C" and D' of members of 2£.A family 2£ of subsets of a set X is a ring of sets if it is closed under 489 use, available at https://www.cambridge.org/core/terms. https://doi