1967
DOI: 10.1007/bf01362285
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A nonpseudocompact product space whose finite subproducts are pseudocompact

Abstract: Abstract. Let {Xi : i ∈ I} be a set of sets, XJ := i∈J Xi when ∅ = J ⊆ I; Y be a subset of XI , Z be a set, and f :

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Cited by 26 publications
(16 citation statements)
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“…[3]. Since (from Corollary 9.12 of [12]) every infinite compact subset of ßN\N has cardinality 2C, each compact subset of A u A is finite.…”
Section: Corollarymentioning
confidence: 99%
“…[3]. Since (from Corollary 9.12 of [12]) every infinite compact subset of ßN\N has cardinality 2C, each compact subset of A u A is finite.…”
Section: Corollarymentioning
confidence: 99%
“…Becausê~ is productive, &* Π Jf = 0. (This space X is similar to spaces constructed in [2]; all are subspaces of βN.) (3) Let tc be an uncountable regular cardinal.…”
Section: (S T) Est{f{s T) and ) V(s T ) E S X T }mentioning
confidence: 99%
“…Terasaka's example (see [8, p. 135]) shows that if X is a countably compact completely regular space, then XxX need not be pseudocompact. Comfort's example in [4] shows that if {X(h) \ neN} are completely regular spaces, then n {X(n) \ne N} is not necessarily pseudocompact even if F] {X(n) | n e B) is pseudocompact for every finite (nonempty) subset B of N. On the other hand, Glicksberg [9] and Bagley, Connell, and McKnight [1] have proved that under certain supplementary hypotheses the product of a collection of pseudocompact completely regular spaces is pseudocompact.…”
Section: Proof (I) Each F(n)mentioning
confidence: 99%
“…We first observe that the following equations hold for any neN and Therefore,/((a, b) n *)e/(U W«)}) = U {/(!>))}<= U {Z(»»<=0. 4. Pseudocompact product spaces.…”
Section: Proof (I) Each F(n)mentioning
confidence: 99%
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