2013
DOI: 10.1007/jhep11(2013)128
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A new pentagon identity for the tetrahedron index

Abstract: Recently Kashaev, Luo and Vartanov, using the reduction from a four-dimensional superconformal index to a three-dimensional partition function, found a pentagon identity for a special combination of hyperbolic Gamma functions. Following their idea we have obtained a new pentagon identity for a certain combination of so-called tetrahedron indices arising from the equality of superconformal indices of dual three-dimensional N = 2 supersymmetric theories and give a mathematical proof of it.

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Cited by 25 publications
(47 citation statements)
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“…More recently it has been called new pentagon identity and plays a role in the study of shaped triangulations, [32]. This identity can also be obtained as a particular limit of the elliptic beta-integral discovered by Spiridonov [33] and has been tested also on the 3d index [34].…”
Section: Jhep08(2016)136mentioning
confidence: 99%
“…More recently it has been called new pentagon identity and plays a role in the study of shaped triangulations, [32]. This identity can also be obtained as a particular limit of the elliptic beta-integral discovered by Spiridonov [33] and has been tested also on the 3d index [34].…”
Section: Jhep08(2016)136mentioning
confidence: 99%
“…Then the integral identity (8) can be written as a pentagon identity [39,13,32,8] Another simple but more interesting example of the pentagon identity is provided by the equality of RP 2 × S 1 partition functions. According to the mirror symmetry we have the following integral identity [40,41,42]…”
Section: Pentagon Identitiesmentioning
confidence: 99%
“…A typical example of the pentagon identity arising from the supersymmetric gauge theories is the equality of the partition functions of three-dimensional N = 2 mirror dual theories which has the following arXiv:1803.00855v1 [math-ph] 2 Mar 2018 form [10,11,12,13,3,8,14] dµ…”
Section: Introductionmentioning
confidence: 99%
“…We then have the biorthogonality relations J(Q (i, j) n Q ( j,i) m ) = 0 for m = n. We may assume that i = 5, j = 6. Then, Q (5,6) n is given by the function (our notation differs from that of Rahman) More precisely, Rahman proved that if…”
Section: Rahman's Biorthogonal Functionsmentioning
confidence: 99%
“…In a similar way, one can obtain basic hypergeometric integrals from three-dimensional theories [6,7,11,12,14,19,41]. Interestingly, the resulting integrals are not of a type considered in the classical literature but involve a mixture of continuous and discrete integration (this can also happen for four-dimensional theories [16,33], but then with a finite rather than infinite discrete component).…”
Section: Introductionmentioning
confidence: 99%