“…= 0, c e 0,2 = 0. The last row comes from(16). Therefore, the estimations of the errors are found asc e 0,1 = 0, c e 1,1 = −0.5769230763 × 10 −11 , c e 2,1 = 0.6615384615 × 10 −10 , c e 0,2 = 0, c e 1,2 = 0.3884615384 × 10 −10 , c e 2,2 = 0.8923076921 × 10 −10 , that is e 1,2 (x) e 2,2 (x) −0.1153846153 × 10 −10 x + 0.7769230768 × 10 −10 x 2 0.7769230768 × 10 −10 x + 0.1153846153 × 10 −10 x 2 .…”