2017
DOI: 10.1007/s11228-017-0400-4
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A Maximum Principle for the Controlled Sweeping Process

Abstract: Abstract. We consider the free endpoint Mayer problem for a controlled Moreau process, the control acting as a perturbation of the dynamics driven by the normal cone, and derive necessary optimality conditions of Pontryagin's Maximum Principle type. The results are also discussed through an example. We combine techniques from [19] and from [6], which in particular deals with a different but related control problem. Our assumptions include the smoothness of the boundary of the moving set C(t), but, differently … Show more

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Cited by 41 publications
(49 citation statements)
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“…t ∈ [0, T ], x(0) = x 0 ∈ C(0), (1. 3) with controls a : [0, T ] → R d acting in perturbations and controls u : [0, T ] → R n acting in the polyhedral moving set generated by the fixed vectors x * i as C(t) := C + u(t) with C := x ∈ R n x * i , x ≤ 0 for all i = 1, . .…”
mentioning
confidence: 99%
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“…t ∈ [0, T ], x(0) = x 0 ∈ C(0), (1. 3) with controls a : [0, T ] → R d acting in perturbations and controls u : [0, T ] → R n acting in the polyhedral moving set generated by the fixed vectors x * i as C(t) := C + u(t) with C := x ∈ R n x * i , x ≤ 0 for all i = 1, . .…”
mentioning
confidence: 99%
“…Control functions appeared there either in additive perturbations [2,3,10,16,31], or in associated ordinary differential equations [1,5]. Necessary optimality conditions for optimal controls in such controlled sweeping models were derived in [3,5] by employing some other methods different from [7,8,12,13] under certain strong smoothness assumptions on the boundaries of compact uncontrolled sweeping sets. In the more recent paper [35], the author addressed relaxation issues for sweeping optimization problems with controls in additive perturbations and uncontrolled convex moving sets that were also included in optimization.…”
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confidence: 99%
“…In this case conditions (6.3) and (5.5) yield q x (t) ≥ 0, and hence we have q x (2) ≤ 0 by (6). It shows that q x (t) = 0 on [1,2] and so ν(t) = −q x (t) = 0, which contradicts the condition ν(t) < 0. Thusū(t) remains constant on [1,2], and we find an optimal solution to this problem.…”
Section: Applications To Elastoplasticity and Hysteresismentioning
confidence: 93%
“…Then it follows from (4.21) and (4.23) that θ 2 = 0, which yields θ 1 = 0 and gives us a contradiction. △ We can directly check that the only optimal trajectory in this problem is given byx(t) = 3/2 on [0, 1/2],x(t) = 2 − t on [1/2, 1], and x(t) = 1 on [1,2], It is generated by the optimal controlū(t) = t − 2 on [0, 1] andū(t) = −1 on (1,2].…”
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confidence: 99%
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