2016
DOI: 10.1090/conm/677/13628
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A logspace solution to the word and conjugacy problem of generalized Baumslag-Solitar groups

Abstract: Baumslag-Solitar groups were introduced in 1962 by Baumslag and Solitar as examples for finitely presented non-Hopfian two-generator groups. Since then, they served as examples for a wide range of purposes. As Baumslag-Solitar groups are HNN extensions, there is a natural generalization in terms of graph of groups.Concerning algorithmic aspects of generalized Baumslag-Solitar groups, several decidability results are known. Indeed, a straightforward application of standard algorithms leads to a polynomial time … Show more

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Cited by 13 publications
(10 citation statements)
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“…The first result in this direction was proved by Lipton and Zalcstein [24] (if the field F has characteristic zero) and Simon [38] (if the field F has prime characteristic): if G is a finitely generated linear group over an arbitrary field F (i.e., a finitely generated group of invertible matrices over F ), then the word problem for G can be solved in deterministic logarithmic space. Related results can be found in [20,43].…”
Section: Introductionmentioning
confidence: 67%
See 1 more Smart Citation
“…The first result in this direction was proved by Lipton and Zalcstein [24] (if the field F has characteristic zero) and Simon [38] (if the field F has prime characteristic): if G is a finitely generated linear group over an arbitrary field F (i.e., a finitely generated group of invertible matrices over F ), then the word problem for G can be solved in deterministic logarithmic space. Related results can be found in [20,43].…”
Section: Introductionmentioning
confidence: 67%
“…An example of group that is not residually finite is the Baumslag-Solitar group BS(2, 3). The word problem for every Baumslag-Solitar group BS(p, q) can be solved in logarithmic space [43].…”
Section: Open Problemsmentioning
confidence: 99%
“…x ≡ k ℓ mod K ℓ (here congruent modulo ∞ means equality). Since the K ℓ are all β-smooth, they can be factored in TC 0 and a solution (if there is one) of this system can be determined in TC 0 (see e. g. [29,Lem. 27]) with the help of Hesse's division circuit [7,8] using the Chinese remainder theorem.…”
Section: Otherwise (And Likewise For G)mentioning
confidence: 99%
“…Note that the conjugacy decision problem over BS (1,2) resides in the complexity class TC 0 [27], where TC 0 is the class of constant-depth arithmetic circuits using AND, OR, NOT, and majority gates.…”
Section: Test Groupsmentioning
confidence: 99%