Number Theory and Applications 2009
DOI: 10.1007/978-93-86279-46-0_7
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A Geometric Framework for the Subfield Problem of Generic Polynomials Via Tschirnhausen Transformation

Abstract: Let k be a field of characteristic = 2. We give an answer to the field intersection problem of quartic generic polynomials over k via formal Tschirnhausen transformation and multi-resolvent polynomials.

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Cited by 7 publications
(19 citation statements)
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“…In Section 3, by using multi-resolvent polynomials, we will give an explicit form of an answer to the field isomorphism problem of f s (X) over K as the special case of the field intersection problem (cf. the simplest cubic case [Mor94], [Cha96], [Oga03], [Kom04], [HM09a], [H]). One of the advantages of using multi-resolvent polynomials is the validity for non-abelian groups (see [HM07], [HM09b], [HM09c], [HM]).…”
Section: Introduction and Main Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…In Section 3, by using multi-resolvent polynomials, we will give an explicit form of an answer to the field isomorphism problem of f s (X) over K as the special case of the field intersection problem (cf. the simplest cubic case [Mor94], [Cha96], [Oga03], [Kom04], [HM09a], [H]). One of the advantages of using multi-resolvent polynomials is the validity for non-abelian groups (see [HM07], [HM09b], [HM09c], [HM]).…”
Section: Introduction and Main Resultsmentioning
confidence: 99%
“…However the multi-resolvent polynomial R 1 f a,b (X) = RP Θ1,U,f a,b (X) where f a,b (X) = f a (X)f b (X) becomes complicated in the both cases above. (i) In [HM09b], we gave an answer to the field isomorphism problem of f s (X) by taking…”
Section: Preliminariesmentioning
confidence: 99%
“…Theorem 4.3 is a generalization of the results of the simplest cubic (resp. quartic) case in [Mor94], [Cha96], [HM09a] (resp. [H2]).…”
Section: By Theorem 34 We Get the Intersection Field Splmentioning
confidence: 99%
“…In the cyclic cubic case, Morton [10] gave an explicit answer to this problem for the generic polynomial X 3 + sX 2 − (s + 3)X + 1 for C 3 over a field K with char K = 2 (see also [1] and [3]). In [2], the authors investigated the field isomorphism problem of f s (X) over a field K with char K = 3 and gave the following theorem: Corollary 8]).…”
Section: Introductionmentioning
confidence: 99%