2002
DOI: 10.37236/1629
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A Generalisation of Transversals for Latin Squares

Abstract: We define a $k$-plex to be a partial latin square of order $n$ containing $kn$ entries such that exactly $k$ entries lie in each row and column and each of $n$ symbols occurs exactly $k$ times. A transversal of a latin square corresponds to the case $k=1$. For $k>n/4$ we prove that not all $k$-plexes are completable to latin squares. Certain latin squares, including the Cayley tables of many groups, are shown to contain no $(2c+1)$-plex for any integer $c$. However, Cayley tables of soluble groups have a $2… Show more

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Cited by 47 publications
(73 citation statements)
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“…Although the concept is much older, the name k-plex was first used in [21]. The definition given in Section 1 is a restriction of the original one.…”
Section: Background and Motivationmentioning
confidence: 99%
See 4 more Smart Citations
“…Although the concept is much older, the name k-plex was first used in [21]. The definition given in Section 1 is a restriction of the original one.…”
Section: Background and Motivationmentioning
confidence: 99%
“…The definition given in Section 1 is a restriction of the original one. In defining a k-plex as a partial Latin square, Wanless [21] allowed that a k-plex be not necessarily completable to a Latin square of the same order. Herein, we are solely concerned with k-plexes which are contained in a Latin square.…”
Section: Background and Motivationmentioning
confidence: 99%
See 3 more Smart Citations