Proceedings of the Forty-Second ACM Symposium on Theory of Computing 2010
DOI: 10.1145/1806689.1806710
|View full text |Cite
|
Sign up to set email alerts
|

A full characterization of quantum advice

Abstract: We prove the following surprising result: given any quantum state ρ on n qubits, there exists a local Hamiltonian H on poly (n) qubits (e.g., a sum of two-qubit interactions), such that any ground state of H can be used to simulate ρ on all quantum circuits of fixed polynomial size. In terms of complexity classes, this implies that BQP/qpoly ⊆ QMA/poly, which supersedes the previous result of Aaronson that BQP/qpoly ⊆ PP/poly. Indeed, we can exactly characterize quantum advice, as equivalent in power to untrus… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
1
1
1
1

Citation Types

0
12
0

Year Published

2012
2012
2023
2023

Publication Types

Select...
3
2
1

Relationship

0
6

Authors

Journals

citations
Cited by 6 publications
(12 citation statements)
references
References 37 publications
0
12
0
Order By: Relevance
“…2 The group non-membership problem is perhaps most naturally described within the black-box group setting [23]. Here, one considers that there is an underlying finite group G n that has been specified for each positive integer n, and elements of G n are encoded as binary strings of length n (so that it must necessarily hold that |G n | ≤ 2 n ).…”
Section: Example: Group Non-membershipmentioning
confidence: 99%
See 4 more Smart Citations
“…2 The group non-membership problem is perhaps most naturally described within the black-box group setting [23]. Here, one considers that there is an underlying finite group G n that has been specified for each positive integer n, and elements of G n are encoded as binary strings of length n (so that it must necessarily hold that |G n | ≤ 2 n ).…”
Section: Example: Group Non-membershipmentioning
confidence: 99%
“…This leads to the class QMA (2). While it is an open question whether or not QMA(2) and QMA are equal, some evidence exists to suggest that QMA(2) is larger than QMA.…”
Section: Unentangled Quantum Proofsmentioning
confidence: 99%
See 3 more Smart Citations