2017
DOI: 10.7155/jgaa.00445
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A Direct Proof of the Strong Hanani-Tutte Theorem on the Projective Plane

Abstract: We reprove the strong Hanani-Tutte theorem on the projective plane. In contrast to the previous proof by Pelsmajer, Schaefer and Stasi, our method is constructive and does not rely on the characterization of forbidden minors, which gives hope to extend it to other surfaces. Moreover, our approach can be used to provide an efficient algorithm turning a Hanani-Tutte drawing on the projective plane into an embedding.

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Cited by 2 publications
(7 citation statements)
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“…and {B3, D3} cross once, but they are all adjacent with a common vertex outside W , the pairs {C1, B3} and {D2, B3} cross twice, and no other pair of edges has a common crossing. To verify condition 2), we use the fact that every vertex of W has the same rotation in D; namely, (1,2,3). Let E be an embedding of G on an orientable surface S such that the rotation of every vertex from W is (1,2,3).…”
Section: Notationmentioning
confidence: 99%
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“…and {B3, D3} cross once, but they are all adjacent with a common vertex outside W , the pairs {C1, B3} and {D2, B3} cross twice, and no other pair of edges has a common crossing. To verify condition 2), we use the fact that every vertex of W has the same rotation in D; namely, (1,2,3). Let E be an embedding of G on an orientable surface S such that the rotation of every vertex from W is (1,2,3).…”
Section: Notationmentioning
confidence: 99%
“…To verify condition 2), we use the fact that every vertex of W has the same rotation in D; namely, (1,2,3). Let E be an embedding of G on an orientable surface S such that the rotation of every vertex from W is (1,2,3). Assume without loss of generality that S has minimum possible genus, which implies that E is a 2-cell embedding.…”
Section: Notationmentioning
confidence: 99%
See 3 more Smart Citations