“…In this paper, we tackle the problem to determine n 5 (5, d) for all d. See [24] for the updated table of n 5 (5, d). The following results are already known for n 5 (k, d), see [1][2][3]5,7,9,11,21,20,25,24,30]. (3) n 5 (4, d) = g 5 (4, d) + 2 for d = 25.…”