“…Because F j ðtÞ and G j ðtÞðj = 1, 2Þ should have the similar characteristics given by Equation ( 3), then from Equations ( 11), ( 12), (13), and ( 14) we obtain a 11 + a 61 = 1, a 12 + a 62 = 0, a 13 + a 63 = 0, a 14 + a 64 = 1, a 11 + a 41 + a 51 = 0, a 12 + a 42 + a 52 = 1, a 13 + a 43 + a 53 = −1, a 14 + a 44 + a 54 = 0, a 21 = 0, a 22 = 0, a 23 = 1, a 24 = 0, a 31 = 0, a 32 = 0, a 33 = 0, a 34 = −1:…”