“…Moreover, taking into account the fact that every finitely presented Z -module M can be presented in the form M ∼ = Hom( A/F A , Q /Z ) for some torsion free group A, see [18], we can deduce from (7) the isomorphism M ∼ = Hom(Hom Z (M, Q /Z ), Q /Z ). Analogously identifying along it, we obtain the equality M = Hom Hom…”