2020
DOI: 10.2422/2036-2145.201711_012
|View full text |Cite
|
Sign up to set email alerts
|

A boxing Inequality for the fractional perimeter

Abstract: We prove the Boxing inequality:is the Hausdorff content of U of dimension d − α and the constant C > 0 depends only on d. We then show how this estimate implies a trace inequality in the fractional Sobolev space W α,1 (R d ) that includes Sobolev's L d d−α embedding, its Lorentz-space improvement, and Hardy's inequality. All these estimates are thus obtained with the appropriate asymptotics as α tends to 0 and 1, recovering in particular the classical inequalities of first order. Their counterparts in the full… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
2
1

Citation Types

1
23
0

Year Published

2020
2020
2024
2024

Publication Types

Select...
7

Relationship

3
4

Authors

Journals

citations
Cited by 16 publications
(24 citation statements)
references
References 33 publications
1
23
0
Order By: Relevance
“…On the one hand, thanks to [28,Theorem 1.2], the fractional α-perimeter P α enjoys the following fractional analogue of Gustin's Boxing Inequality (see [19] and [16, (1.14)…”
mentioning
confidence: 99%
“…On the one hand, thanks to [28,Theorem 1.2], the fractional α-perimeter P α enjoys the following fractional analogue of Gustin's Boxing Inequality (see [19] and [16, (1.14)…”
mentioning
confidence: 99%
“…One deduces from Proposition 2.1 and a straightforward adaptation of the proof of Theorem 2.1 in [13] the following:…”
Section: Non-homogeneous Boxing Inequalitymentioning
confidence: 87%
“…The plan of the paper is as follows. In Section 2 we show how recent work of the authors [13] on the Boxing inequality of Gustin implies a nonhomogeneous form of this inequality that involves the Choquet integral with respect to the Hausdorff outer measures H d−α δ for 0 < α ≤ d and 0 < δ < ∞. In this range of α such an estimate is equivalent to the strong capacitary inequality in Theorem 1.2.…”
Section: Introductionmentioning
confidence: 90%
See 1 more Smart Citation
“…for all non-negative Radon measures µ such that µ(B(x, r)) ≤ C ′ r d−α then as in Lemma 4.6 in[15] it would implŷR d |u| dH d−α ∞ ≤ CˆR d |D α u|, which when combined with equation (1.16) would yield…”
mentioning
confidence: 95%