1999
DOI: 10.2307/3620958
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83.47 The Secret Santa problem

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Cited by 6 publications
(7 citation statements)
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“…We prove that every non-negative integer N can be written uniquely in the form N = fli.l! + a 2 .2\ + ... + a p .p\ (1) where 0 < a, < /fori = 1, 2, ... ,p. This result depends on the known p summation X i.i\ + 1 = (p + 1)!.…”
Section: Appendixmentioning
confidence: 94%
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“…We prove that every non-negative integer N can be written uniquely in the form N = fli.l! + a 2 .2\ + ... + a p .p\ (1) where 0 < a, < /fori = 1, 2, ... ,p. This result depends on the known p summation X i.i\ + 1 = (p + 1)!.…”
Section: Appendixmentioning
confidence: 94%
“…Clearly the right-hand side of (1) gives a unique non-negative integer. We must now show, conversely, how to write any given non-negative integer in the form (1). This is done by induction on N.…”
Section: Appendixmentioning
confidence: 99%
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“…In the light of [2] it now emerges that, by adopting a different approach from that given in [1], we can solve completely every linear second-order difference equation with variable coefficients with reasonable economy of effort. Here, we develop the method of solution for a general second-order equation and illustrate it by applying it to a particularly intractable difference equation, namely that which arises in the secret-Santa problem [3]. {The Secret Santa problem may be stated: All the students in a class write their names on slips of paper which are placed in a box and shuffled.…”
Section: Introductionmentioning
confidence: 99%
“…Some published works in social sciences exist [3]. A scholarly discussion ensued in 1999-2001 in the Mathematical Gazette [7,9,1] focussing on the probability of picking a gift assignment without mutual gifts. This is extended in [8] to deal with more constraints on pairs of people that cannot exchange gifts, and in [13] to include at least a cyclic assignment of given length.…”
Section: Introductionmentioning
confidence: 99%