Handbook of Applied Algorithms 2007
DOI: 10.1002/9780470175668.ch12
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2D Shape Measures for Computer Vision

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Cited by 10 publications
(6 citation statements)
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“…In addition, there are some general approaches to defining shape descriptors that could be adopted to defining squareness [22]. For example, first, fit (somehow) a square K f it (S) to a measured shape S, and then estimate the squareness of the shape S by comparing K f it (S) and S. One straightforward possibility for a fitted square K f it (S) is the square whose centroid coincides with the centroid of S, whose area is equal to the area of S, and finally K f it (S) is rotated such that the area of K f it (S)∩S is maximised.…”
Section: Introductionmentioning
confidence: 99%
“…In addition, there are some general approaches to defining shape descriptors that could be adopted to defining squareness [22]. For example, first, fit (somehow) a square K f it (S) to a measured shape S, and then estimate the squareness of the shape S by comparing K f it (S) and S. One straightforward possibility for a fitted square K f it (S) is the square whose centroid coincides with the centroid of S, whose area is equal to the area of S, and finally K f it (S) is rotated such that the area of K f it (S)∩S is maximised.…”
Section: Introductionmentioning
confidence: 99%
“…Обычно авторы рассматривают задачу в случае, если области из нулей имеют регулярную структуру или их не так много. К примеру, заранее известны позиции K нулевых точек [8,9] или нулевые области имеют форму отрезков [10]. В таких случаях удается построить эффективные алгоритмы.…”
unclassified
“…The main contribution of [4] is to replace the diagonal constraint matrix C by a matrix which corresponds to the condition 4ac-b 2 =1, which then always produces an ellipse. Such a matrix C satisfies a T Ca = 1 and has all zeros except C 13…”
Section: Direct Least Square Fittingmentioning
confidence: 99%
“…The problem now is to minimize a 1 T S 1 a 1 subject to a 1 T C'a 1 =1, where C' is the top 3x3 sub-matrix from C (nonzero elements are C' 13…”
Section: Then G = a 1 T S 11 A 1 + A 1 T S 12 A 2 =A 1 T (S 1 1 -S mentioning
confidence: 99%
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