We
have quantum chemically analyzed the competition between the
bimolecular nucleophilic substitution (S
N
2) and base-induced
elimination (E2) pathways for F
–
+ CH
3
CH
2
Cl and PH
2
–
+ CH
3
CH
2
Cl using the activation strain model and Kohn–Sham
molecular orbital theory at ZORA-OLYP/QZ4P. Herein, we correct an
earlier study that intuitively attributed the mechanistic preferences
of F
–
and PH
2
–
, i.e.,
E2 and S
N
2, respectively, to a supposedly unfavorable shift
in the polarity of the abstracted β-proton along the PH
2
–
-induced E2 pathway while claiming that
″
...no correlation between the thermodynamic basicity
and E2 rate should be expected.
″ Our analyses, however,
unequivocally show that it is simply the 6 kcal mol
–1
higher proton affinity of F
–
that enables this
base to engage in a more stabilizing orbital interaction with CH
3
CH
2
Cl and hence to preferentially react via the
E2 pathway, despite the higher characteristic distortivity (more destabilizing
activation strain) associated with this pathway. On the other hand,
the less basic PH
2
–
has a weaker stabilizing
interaction with CH
3
CH
2
Cl and is, therefore,
unable to overcome the characteristic distortivity of the E2 pathway.
Therefore, the mechanistic preference of PH
2
–
is steered to the S
N
2 reaction channel (less-destabilizing
activation strain).