1971
DOI: 10.1002/j.1538-7305.1971.tb02556.x
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1969-70 Connection Survey: Analog Transmission Performance on the Switched Telecommunications Network

Abstract: To characterize the transmission performance of the Bell System switched telecommunications network, Bell Telephone Laboratories conducted a survey of toll connections during 1969 and 1970. Connections were established between Bell System end offices chosen by statistical sampling techniques. Both analog and data transmission tests were performed. A summary of analog transmission performance is presented in this paper. It contains estimates for noise, loss, attenuation distortion, envelope delay distortion, pe… Show more

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Cited by 35 publications
(7 citation statements)
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“…e j2,t 30<t<NT, T=* , fn= equivalently, x(t) is a sum of sinusoidal signals whose amplitudes are determined by the sets of data values {A5} and {B5} , as depicted in figure (2). This interpretation makes the transmitter an implementation of a frequency division multiplexing (FDM) system [lj If the signal x(t) is transmitted thru a linear channel with impulse response h(t) and frequency response H(w) , then the signal at the output of the channel s(t) is determined by the convolution of x(t) and h(t) , or in the frequency domain by S(w) H(w).X(w).…”
Section: Frequency Domain Data Transmissionmentioning
confidence: 99%
See 1 more Smart Citation
“…e j2,t 30<t<NT, T=* , fn= equivalently, x(t) is a sum of sinusoidal signals whose amplitudes are determined by the sets of data values {A5} and {B5} , as depicted in figure (2). This interpretation makes the transmitter an implementation of a frequency division multiplexing (FDM) system [lj If the signal x(t) is transmitted thru a linear channel with impulse response h(t) and frequency response H(w) , then the signal at the output of the channel s(t) is determined by the convolution of x(t) and h(t) , or in the frequency domain by S(w) H(w).X(w).…”
Section: Frequency Domain Data Transmissionmentioning
confidence: 99%
“…We also define the updated equalizer for the k + 1n frame Since the subsequence frame boundary is out of synchronization, Dk (12a) the receiver picks-up a time shifted version of the response of the = k channel to the repeated PN subsequence. Based on the spectral characteristics of the telephone channel, as obtained in the last survey on analog transmission performance of telephone lines [2] , allocation of frequency bins can be made as shown in fig. (3).…”
Section: N-imentioning
confidence: 99%
“…With 20 RTUs allocated to the EOCS* at least 380 basic experi-• Examination of data from Ref. 7 suggests that one deployment of 20 RTUs would be sufficient to achieve the goals of the study. As we noted, the sample was required to adequately represent various strata.…”
Section: Remote Test Unit Location Samplingmentioning
confidence: 99%
“…By analyzing a recent survey of voiceband channels [9], it was found that a good compromise between performance and complexity was to consider that the first leading and trailing echoes i_, and *, are dominant, and also that the second trailing echo ij is small enough to allow approximating (9) by (10) where fi^ is considered as additional noise. In (10), e and 0, which will be termed "phase echoes," can take on 16 and 4 possible values, respectively, depending on the data sequence transmitted.…”
Section: Receiver Processesmentioning
confidence: 99%