2005
DOI: 10.1007/11498490_25
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19 Model Checking

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Cited by 10 publications
(27 citation statements)
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“…Proof: This follows directly from the proof of correctness and complexity of Rivest and Schapire's algorithm [4,22]. Notice that the equivalence query cannot return a counterexample whose normal form uses more than k registers, as such a word is rejected by both A C (by definition) and by A O , (by construction).…”
Section: Learning Session Automatamentioning
confidence: 99%
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“…Proof: This follows directly from the proof of correctness and complexity of Rivest and Schapire's algorithm [4,22]. Notice that the equivalence query cannot return a counterexample whose normal form uses more than k registers, as such a word is rejected by both A C (by definition) and by A O , (by construction).…”
Section: Learning Session Automatamentioning
confidence: 99%
“…Since A C only accepts symbolic words which are in normal form, a membership query for a given symbolic word u not in normal form will be answered negatively (without consulting the teacher); otherwise, the teacher will be given one data word included in γ(u) (all the answers on words of γ(u) are the same). Likewise, before submitting an equivalence query to the teacher, the learning algorithm checks if the current hypothesis automaton accepts symbolic words not in normal form 4 . If yes, one of those is taken as a counterexample, else an equivalence query is submitted to the teacher.…”
Section: Learning Session Automatamentioning
confidence: 99%
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