2019
DOI: 10.48550/arxiv.1902.08109
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The fluctuations of the giant cluster for percolation on random split trees

Abstract: A split tree of cardinality n is constructed by distributing n "balls" (which often represent "key numbers") in a subset of vertices of an infinite tree. In this work, we study Bernoulli bond percolation on arbitrary split trees of large but finite cardinality n. We show for appropriate percolation regimes that depend on the cardinality n of the split tree that there exists a unique giant cluster that is of size comparable of that of the entire tree (where size is defined as either the number of vertices or th… Show more

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Cited by 3 publications
(4 citation statements)
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“…1,n → e −c/µ , in distribution, as n → ∞, which proves the second assertion. Moreover,[6, Lemma 2] also shows that C * 1 /n 1,n → 0, in distribution, as n → ∞, and by Corollary 1, we conclude that C * 1 = o p (n/ ln n). This completes the proof.d − → (x 1 , .…”
supporting
confidence: 55%
“…1,n → e −c/µ , in distribution, as n → ∞, which proves the second assertion. Moreover,[6, Lemma 2] also shows that C * 1 /n 1,n → 0, in distribution, as n → ∞, and by Corollary 1, we conclude that C * 1 = o p (n/ ln n). This completes the proof.d − → (x 1 , .…”
supporting
confidence: 55%
“…Without going into details, we note that the proof of (13.5) in [7], as well as our similar proof in Section 13.1, is based on showing the two results (12.3) and (12.4), and that (12.3) was shown by Holmgren [23].…”
Section: Split Treesmentioning
confidence: 75%
“…Proof of Theorem 2. The first claim has been proved in [6,Lemma 3], and thus, we only prove the second one. Following exactly the same argument as in the proof of Corollary 2, we deduce from Corollary 1 and Proposition 3 that for every fixed i ∈ N,…”
Section: Proposition 3 Suppose That Conditions 1 and 2 Hold And That ...mentioning
confidence: 88%
“…That is, [6, Lemma 3] implies that C j ∕n j,n P → 𝛼e −c∕𝜇 , as n → ∞ which proves the second assertion. Moreover, [6,Lemma 3] also shows that C * j ∕n j,n P → 0, as n → ∞, and by Corollary 1, C * j = o p (n∕ ln n). ▪…”
Section: Proposition 3 Suppose That Conditions 1 and 2 Hold And That ...mentioning
confidence: 92%