2013
DOI: 10.1111/jace.12222
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Synthesis of Y3Al5O12:Eu2+ Phosphor by a Facile Hydrogen Iodide‐AssistedSol–Gel Method

Abstract: Pure yttrium aluminum garnet (YAG) phosphor doped with Eu2+ has been successfully synthesized by a facile sol–gel method. The use of hydrogen iodide aimed to get Eu2+ ions, confirmed by X‐ray absorption near‐edge structure (XANES) analysis. Nearly spherical and well dispersed particles were synthesized. The produced YAG:Eu2+ phosphor powder had a broad emission band in the range of 400–600 nm with a peak at 480 nm, attributed to the allowed 4f7–4f65d1 transition of electrons in Eu2+ ions. The proposed method c… Show more

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Cited by 26 publications
(22 citation statements)
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“…It should be noted that sharp lines assigned to Eu 3+ intra‐4 f 6 transitions have been detected, indicating that there are Eu 3+ ions in the crystal. However, YSiON–HI: 0.02Eu compounds are effectively excited by 270 nm and 343 nm, and it exhibits blue broad emission band ranging from 400 to 500 nm centered at 437 nm, which is an obvious characteristic of the 4 f 6 5 d →4 f 7 transitions of Eu 2+ ions in Y 4 Si 2 O 7 N 2 crystal lattice . In addition, the luminescence assigned to Eu 3+ completely disappears in YSiON–HI: 0.02Eu.…”
Section: Resultsmentioning
confidence: 97%
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“…It should be noted that sharp lines assigned to Eu 3+ intra‐4 f 6 transitions have been detected, indicating that there are Eu 3+ ions in the crystal. However, YSiON–HI: 0.02Eu compounds are effectively excited by 270 nm and 343 nm, and it exhibits blue broad emission band ranging from 400 to 500 nm centered at 437 nm, which is an obvious characteristic of the 4 f 6 5 d →4 f 7 transitions of Eu 2+ ions in Y 4 Si 2 O 7 N 2 crystal lattice . In addition, the luminescence assigned to Eu 3+ completely disappears in YSiON–HI: 0.02Eu.…”
Section: Resultsmentioning
confidence: 97%
“…According to the above results, the authors think that the chemical characteristic of HI (the strong acidic and reducing properties) contributes to doping Eu 2+ ions in the YSiON–HI: 0.02Eu. The reaction between Eu 2 O 3 and HI can be formulated as:Eu2normalO3+6HI2EuI3+3normalH2O…”
Section: Resultsmentioning
confidence: 99%
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“…Homogeneity of the raw materials in the precursor can make all of the components react more equally during the calcination process. Thus, fine particles with a narrow size distribution can be achieved at a lower calcination temperature . Figure c shows that the high synthesis temperature of 1600°C leads to severe agglomeration and irregular particle shape, as that happens in high‐temperature solid‐state reaction method…”
Section: Resultsmentioning
confidence: 99%