1996
DOI: 10.1016/0277-5387(95)00397-5
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Synthesis and spectral studies of some new palladium(II) and platinum(II) dithio complexes: The novel crystal structure of the palladium(II) dithiocarbimato complex

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Cited by 17 publications

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“…c S-stereoisomer. Two di-anionic palladium(II) complex molecules adopt the square planar motif illustrated in Figure 6a: {Pd[S2C=N(CN)]2} 2− in 13 [19] and {Pd[S2C=N(C6H4NH2-4)]} 2− in 14 [23]. The palladium atoms in the two independent di-anions in the asymmetric unit of 13 and in the di-anion in 14 are each located on a center of inversion.…”
Section: Ni Group
mentioning
confidence: 99%
“…Another general procedure for the formation of dithiocarbimate complexes involves the conversion of a pre-formed dithiocarbamate complex to the dithiocarbimate derivative. As an example of this method, [NBu 4 ] 2 {Pd[S 2 C=N(C 6 H 4 NH 2 -4)] 2 } [23] was prepared from the reaction of Pd[S 2 CN(H)C 6 H 4 NH 2 -4] 2 with excess NaOH, whose function is to abstract the S 2 CN-bound proton from the dithiocarbamate complex, followed by the addition of tetrabutylammonium bromide to yield the dithiocarbimate complex.…”
Section: General Aspects Of Dithiocarbimate Ligands
mentioning
confidence: 99%
“…Despite having monodentate phosphane ligands, the molecules in each of (Me 3 P) 2 Pd[S 2 C=N(Ph)] (15) [35], (Et 3 P) 2 Pd[S 2 C=N(CH 2 Ph)] ( 16) [22], (Me 2 PhP) 2 Pt[S 2 C=N(Ph)] (17) [35], (Ph 3 P) 2 Pd[S 2 C=N (C(=O)OEt)] (18) [36], and (Ph 3 P) 2 Pd[S 2 C=N(2-py)] ( 19) [37] adopt the same motif shown in Figure 6b. In the same way, the platinum(II) complexes with two monodentate phosphane ligands (i.e., (Et 3 P) 2 Pt[S 2 C=N(CH 2 Ph)] (20) [22], (Me 2 PhP) 2 Pt[S 2 C=N(Ph)] ( 21) [38], (Me 2 PhP) 2 Pt[S 2 C=N(CN)] ( 22) [19], and (Ph 3 P) 2 Pt[S 2 C=N(Me)] ( 23) [39]) adopt the motif shown in Figure 6b, as do the analogs with bidentate phosphane ligands, i.e., the R-( 24) and S-stereoisomers ( 25 Two di-anionic palladium(II) complex molecules adopt the square planar motif illustrated in Figure 6a: {Pd[S2C=N(CN)]2} 2-in 13 [19] and {Pd[S2C=N(C6H4NH2-4)]} 2-in 14 [23]. The palladium atoms in the two independent di-anions in the asymmetric unit of 13 and in the di-anion in 14 are each located on a center of inversion.…”
Section: Ni Group
mentioning
confidence: 99%
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