“…From the proof of Proposition 4.9 we already know that λ ∈ σ ess (L) if and only if Z r1 11 −λ and M 4 −λ are Fredholm operators on L 2 (0, r 1 ), 1 r 3 and L 2 (r 1 , r 0 ), 1 r 2 , respectively, for any r 1 ∈ (0, r 0 ]. But M 4 − λ is invertible by [7,Proposition 2.3]. Note that Z r1 11 has the same form as Z, just considered on a subinterval, because in the definition of V + f we can replace the upper limit r 0 in the integral by r 1 since the function f has support in [0, r 1 ].…”