1996
DOI: 10.1002/(sici)1098-2418(199603)8:2<97::aid-rsa1>3.0.co;2-j
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Scrambling permutations and entropy of hypergraphs
Abstract: The following result is proved by using entropy of hypergraphs. If r , , . . . , r,, are permutations of the n element set P such that for every triple x , y , z E P, one can find a ri such that ~~( x )is between r i ( y ) and r i ( z ) , then n < exp(d/2). We also study k-scrambling permutations. Several problems remained open. @ 1996 John Wiley & Sons, Inc. MIXING PERMUTATIONS AND A CONTAINMENT PROBLEM OF ORTHANTSThe permutations 7rl, . . . , 7rd of the n-element set P are called 3-mixing if for any 3-elemen…
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Cited by 26 publications
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“…Although our interest in this paper is in determining the exact value of g(n, k) for small n and k, we summarize in Theorems 2.10 and 2.11 below the best known asymptotic bounds on the growth rate of g(n, k) as n and k grow. These results improve on previous asymptotic results for completely scrambling sets [19,10,6,18]. Theorem 2.10 holds for general k, and was proved by combining combinatorial arguments with a result due to Wilson [22,Thm.…”
Section: Previous Results For G(n K)supporting
confidence: 84%
“…Although our interest in this paper is in determining the exact value of g(n, k) for small n and k, we summarize in Theorems 2.10 and 2.11 below the best known asymptotic bounds on the growth rate of g(n, k) as n and k grow. These results improve on previous asymptotic results for completely scrambling sets [19,10,6,18]. Theorem 2.10 holds for general k, and was proved by combining combinatorial arguments with a result due to Wilson [22,Thm.…”
Section: Previous Results For G(n K)supporting
confidence: 84%
“…If such a family exists, we may assume that the triple that is not shattered contains the element 5. From this we see that the family of 6 permutations of S 4 generated by omitting 5 must shatter every triple from [4]. Since the family Q k (4) is unique up to isomorphism, to prove the statement we show that adding 5 in any position to permutations from Q k (4) results in a family that leaves 2 triples un-shattered.…”
Section: Appendix Amentioning
confidence: 88%
“…by Janson's inequality (see[1] Theorem 8.1.1) and the last inequality thatPr[∩ U A(U )] ≤ e −µ/2 ≤ e −0.5h −h n h(α− a(H) a * )+ a(H) a * = o(n −2hn α )where in the last inequality we have used thath(α − a(H) a * ) + a(H) a * > αwhich indeed holds by(5). Consider next the case where ∆ ≥ µ. …”
mentioning
confidence: 89%
