1969
DOI: 10.1039/j39690002053
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Quinone epoxides. Part III. Stereospecific reductions with metal hydrides

Abstract: Reduction of 1.4-naphthoquinone epoxide with sodium borohydride (1 equiv.) is shown to give the isomeric r-2.3-epoxy-3.4-dihydro-c-4-hydroxynaphthalen-I (2H)-one ( I I I a ) and r-2,3-epoxy-3,4-dihydro-t-4-hydroxynaphthalen-I (2H)-one ( I I I b ) in a ratio of ca. 11 : 1. With the same reagent juglone epoxide (5-hydroxy-I ,4naphthoquinone epoxide) is selectively and stereospecificalty reduced a t the chelated carbonyl to give r-2.3-epoxy-3,4-dihydro-c-4,5-dihydroxynaphthaten-l(2H) -one (IX) as the major produc… Show more

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Cited by 9 publications
(23 citation statements)
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“…In addition, observation of four pairs of signals with very similar 13 C NMR chemical shifts (Table 1) suggested a pseudo-symmetrical structure. The NMR shifts for two of the oxymethine units (δ C 55.9 and 55.5/δ H 3.40 and 3.38) were diagnostic for the presence of a 1,2-disubstituted epoxide.…”
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confidence: 97%
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“…In addition, observation of four pairs of signals with very similar 13 C NMR chemical shifts (Table 1) suggested a pseudo-symmetrical structure. The NMR shifts for two of the oxymethine units (δ C 55.9 and 55.5/δ H 3.40 and 3.38) were diagnostic for the presence of a 1,2-disubstituted epoxide.…”
mentioning
confidence: 97%
“…7,8 Interestingly, the relative stereochemistry of phaeofuran A (1) was readily assigned on the basis of symmetry considerations. Of the three possible diastereomeric structures of phaeofuran A, two of them have H-4 and H-7 cis to each other, leading to a plane of symmetry that would give rise to an achiral molecule showing only three 1 H NMR methine signals and four 13 C NMR signals. Therefore, H-4 and H-7 must be trans to each other in phaeofuran A, thereby establishing the relative stereochemistry as shown in 1.…”
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confidence: 99%
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