“…In order to demonstrate the effect of different interleaving depths we need to keep the packet size constant. We keep the product vI constant by choosing the following pairs of (I, v): (1, 16), (2,8), (4,4), (8,2), (16, 1). With this choice of (I, v) the whole packet size (including all headers) is always 63×16 = 1008 bits (126 bytes).…”