1996
DOI: 10.1002/mana.3211810105
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On a Geometric Formula for the Fundamental Solution of Subelliptic Laplacians

Abstract: Abrtract. This paper introduces a new method for constructing fundamental solutions and parametricen for a class of second order subelliptic operators. The method is applied to obtain an explicit fundamental solution for the sublaplacian associated to the hypersurface { Im z2 = (51 Ilk} C C '. The fundamental solution is expressed aa an integral over the characteristic variety of an expression whose denominator is a Hamiltonian action function and whose numerator solves an associated second order transport equ… Show more

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Cited by 63 publications
(54 citation statements)
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“…In relation with our results, the paper [12] gives a deep aspect for the construction of the heat kernel of the higher step Grushin operator and partly constructed the heat kernel (also see [13,14] where Green kernels and heat kernels were constructed for a class of higher step Grushin ''type'' operators).…”
Section: + O(t))mentioning
confidence: 91%
“…In relation with our results, the paper [12] gives a deep aspect for the construction of the heat kernel of the higher step Grushin operator and partly constructed the heat kernel (also see [13,14] where Green kernels and heat kernels were constructed for a class of higher step Grushin ''type'' operators).…”
Section: + O(t))mentioning
confidence: 91%
“…The integral path may be deformed to a contour Γ in the complex plane, such that the integration is taken on the best behavior of the integrand such that the integral is well-defined, for example, Γ is the whole imaginary axis or the contour discussed in Chang et al [14]. See also Beals et al [2,3] and Calin et al [8]. The function f is called the modified (complex) action which plays the same role as the square of the distance function and satisfies the eiconal equation:…”
Section: The Modified Action Function First We Need the Classical Acmentioning
confidence: 99%
“…For simplicity we follow the ideas of [7,24], and assume that the volume element v is represented as v = V Subtracting (9.3) from (9.4) we arrive at…”
Section: Volume Elementmentioning
confidence: 99%