2008
DOI: 10.1016/j.jctb.2008.02.008
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Nowhere-zero 3-flows in triangularly connected graphs

Abstract: Let H 1 and H 2 be two subgraphs of a graph G. We say that G is the 2-sum of H 1 and H 2 , denoted byA connected graph G is triangularly connected if for any two edges e and e , which are not parallel, there is a triangle-path T 1 T 2 · · · T m such that e ∈ E(T 1 ) and e ∈ E(T m ). Let G be a triangularly connected graph with at least three vertices. We prove that G has no nowhere-zero 3-flow if and only if there is an odd wheel W and a subgraph G 1 such that G = W ⊕ 2 G 1 , where G 1 is a triangularly connec… Show more

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Cited by 43 publications
(29 citation statements)
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“…The main idea in our approach is to find a specific class of subgraphs, recently called triangularly connected subgraphs (Fan et al , 2008), by iterating over edges instead of triangles, as explained in more detail below.…”
Section: Resultsmentioning
confidence: 99%
“…The main idea in our approach is to find a specific class of subgraphs, recently called triangularly connected subgraphs (Fan et al , 2008), by iterating over edges instead of triangles, as explained in more detail below.…”
Section: Resultsmentioning
confidence: 99%
“…. , C k such that e 1 ∈ E(C 1 ) and and H 2 be two subgraphs of a graph G. We say that G is the 2-sum of H 1 and H 2 , denoted by [2][3][4]7,8]). Let A be an abelian group with |A| ≥ 3.…”
Section: Known Resultsmentioning
confidence: 99%
“…Contracting this wheel W 4 and contracting the 2-cycle generated in the process, we get K 1 . By parts (1), (3), (5) and (6) Lemma 2.6 shows that there exists a nowhere-zero…”
Section: Lemma 25 a Graph G Is 3-flowable If And Only If G Admits A mentioning
confidence: 87%
“…(4) K m,n is A-connected if m ≥ n ≥ 4; neither K 2,t (t ≥ 2) nor K 3,s (s ≥ 3) is Z 3 -connected; (5) Each even wheel is Z 3 -connected and each odd wheel is not; (6) Let H ⊆ G and H be A-connected. G is A-connected if and only if G/H is A-connected; (7) If G is not A-connected, then any spanning subgraph of G is not A-connected.…”
Section: Lemma 22 Letmentioning
confidence: 99%