1925
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Abstract: From this equation we know that -, molecule ('07.92 g) of potassium bromate corresponds to 0 atoms (479.5 g.) of bromine, or 4-4 C.c. of Mj20 KBr0 3 to 0.'053 g. of bromine.And 0034 g. of cysteine hydrochloride contains 0.020' g. of cysteine.Consequently one molecule of cysteine (Ln. '4 g.) corresponds to 488.7 g.(about 6 atoms) of bromine. 12 I. 14 x 0.1053/0.0261 = 488.7 (b). 0.034 g. of cysteine hydro~hlorid~ was dissolveu in 20 C.C. of 10 per cent hydrochloric acid and th~n titrated with 0 33 per cent brom… Show more

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