2016
DOI: 10.1016/j.enbuild.2015.10.027
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Modeling and simulation of the heating circuit of a multi-functional building

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Cited by 26 publications
(10 citation statements)
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“…Moreover, the heating and cooling demands of the building are covered through low‐temperature heating and high‐temperature cooling networks using a variety of energy supply technologies such as Façade Ventilation Unit (FVU), Active Chilled Beam (ACB), Concrete Core Activation (CCA), Underfloor Heating (UFH), etc. For more information about the energy concept of the building see References and .…”
Section: Case Studymentioning
confidence: 99%
“…Moreover, the heating and cooling demands of the building are covered through low‐temperature heating and high‐temperature cooling networks using a variety of energy supply technologies such as Façade Ventilation Unit (FVU), Active Chilled Beam (ACB), Concrete Core Activation (CCA), Underfloor Heating (UFH), etc. For more information about the energy concept of the building see References and .…”
Section: Case Studymentioning
confidence: 99%
“…The first step includes using some applicable tools from the field of system projecting determined for identification an existing or planned system within the real world and, consequently, transforming the identified system into a mathematic model form (Sangi et al, 2016). This form should take into consideration the above mentioned analogy between electronic and heat circuits for physical parameters to be definitely assigned and processed by the analytic software.…”
Section: Mathematic Model Constructionmentioning
confidence: 99%
“…The temperature values and their time courses are the most important quantities for state changes examining in the given points and, therefore, the equation (17) must be adjusted so that the heating nods matrix would be in the left side: (18) or in the full form: (19) where …”
Section: (17b)mentioning
confidence: 99%
“…thermal mass of the floor is calculated as: Volume of the floor = length  width  height = 12  2.4  0.075 = 2.16 m 3 Density of concrete = = 2300 kg/ m 3 mass = M = 2.16  2300 = 4968 kg specific heat of concrete = Cp = 880 J/kg.K heat transfer = Ph = MCpT = 4968  880  T = 4371840TT = Ph/4371840 ……….…….…… (8). …”
mentioning
confidence: 99%