1978
DOI: 10.1007/bf00181353
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Inversive geometry and some new translation planes, I

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Cited by 24 publications
(38 citation statements)
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“…This last case does not occur in PG (3,7). LEMMA 3.1 Every spread in PG(3,7) contains at least four lines from a regulus.…”
Section: Finding the Spreadsmentioning
confidence: 90%
See 2 more Smart Citations
“…This last case does not occur in PG (3,7). LEMMA 3.1 Every spread in PG(3,7) contains at least four lines from a regulus.…”
Section: Finding the Spreadsmentioning
confidence: 90%
“…Let G be the intersection graph of the lines of PG (3,7). Then G has 2850 vertices and a spread of PG (3,7) is an independent set of size 50 inside G. The automorphism group of G is not P FL (4, 7) so independent sets that are equivalent under Aut(G) are not necessarily equivalent under PFL (4,7).…”
Section: Proof (By Computer)mentioning
confidence: 99%
See 1 more Smart Citation
“…It turns out that this spread contains 7 reguli. 4 ͘ accordingly as q ϵ 1 (mod 4) or q ϵ 3 (mod 4). Our previous work shows that D is contained in the translation complement of ȏ.…”
Section: Using the Above Notation Either T Ker T B Or T B Is An Elmentioning
confidence: 99%
“…By Theorem 1 the only circles contained in the point set Ũ are the circles of Ñ , and hence Aut( 4 , where Z (qϩ1)/2 denotes the cyclic group of order (q ϩ 1)/2 and K 4 denotes the Klein 4-group. In practice, G ϭ Aut(Ñ ), as has been verified for q Յ 19.…”
Section: Theorem 2 (Schmidtmentioning
confidence: 99%