2017
DOI: 10.1063/1.4985627
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Hydrogen anion and subgap states in amorphous In–Ga–Zn–O thin films for TFT applications

Abstract: Hydrogen is an impurity species having an important role in the physical properties of semiconductors. Despite numerous studies, the role of hydrogen in oxide semiconductors remains an unsolved puzzle. This situation arises from insufficient information about the chemical state of the impurity hydrogen. Here, we report direct evidence for anionic hydrogens bonding to metal cations in amorphous In–Ga–Zn–O (a-IGZO) thin films for thin-film transistors (TFT) applications and discuss how the hydrogen impurities af… Show more

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Cited by 129 publications
(107 citation statements)
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“…The H -can be placed at the oxygen vacancy site and then form the metal-hydrogen bond (M-H) which is thermally stable. 26 Therefore, this does not change after annealing at 300 o C. On the other hand, H + in a-IGZO reacts with O 2-and donates one electron by the following reaction;…”
Section: Aip Advances 7 125110 (2017)mentioning
confidence: 98%
“…The H -can be placed at the oxygen vacancy site and then form the metal-hydrogen bond (M-H) which is thermally stable. 26 Therefore, this does not change after annealing at 300 o C. On the other hand, H + in a-IGZO reacts with O 2-and donates one electron by the following reaction;…”
Section: Aip Advances 7 125110 (2017)mentioning
confidence: 98%
“…[4,5] In particular, the instability under negative-bias-illumination-stress (NBIS) is known to be most serious. [6,7] Among the suggested mechanisms of the NBIS instability, the oxygen vacancy (V O ) has been receiving intensive attention because AOS films are oxygen deficient. [8][9][10][11][12] The role of V O in the device instability critically depends on its nature, specifically, whether defect levels associated with V O is shallow or deep.…”
Section: Introductionmentioning
confidence: 99%
“…Thus, the increase of I off in the passivated device was attributed to the byproduct hydrogen during the deposition of SiO x . Because neutral H 0 could migrate in the channel layer and further react with O 2− to form OH − and generate excessive electrons (H0+O2OH+e), which would result in the formation of back-channel current (I back ), as shown in Figure 2b [19]. …”
Section: Resultsmentioning
confidence: 99%