Representations of Reductive Groups 1998
DOI: 10.1017/cbo9780511600623.006
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Generalized Harish-Chandra theory

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Cited by 64 publications
(146 citation statements)
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“…If b = NE(a), then N(a) is attached to neither its NE nor its SE neighbour, so is the end node of its tile, and in particular dp(N(a)) = 0. On the other hand dp(a) > dp(b) 0, contradicting (2). If instead b = SE(a), then NE(a) is attached to neither its NW nor its SW neighbour, so is the start node of its tile, and has depth 0; but dp(b) > dp(a) 0, and again (2) is contradicted.…”
Section: Proofmentioning
confidence: 91%
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“…If b = NE(a), then N(a) is attached to neither its NE nor its SE neighbour, so is the end node of its tile, and in particular dp(N(a)) = 0. On the other hand dp(a) > dp(b) 0, contradicting (2). If instead b = SE(a), then NE(a) is attached to neither its NW nor its SW neighbour, so is the start node of its tile, and has depth 0; but dp(b) > dp(a) 0, and again (2) is contradicted.…”
Section: Proofmentioning
confidence: 91%
“…If both SE(l) and SW(l) lie in μ, then l is an addable node and we are in case (1). If neither lies in μ, then S(l) is a removable node, and we are in case (2). If SE(l) ∈ μ / SW(l), then we are in case (3), while if SE(l) / ∈ μ SW(l) then we are in case (4).…”
Section: Proof Of Theorem 52mentioning
confidence: 99%
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“…Let Φ = T 1 T 2 T 3 . It follows from the computation of the generic degrees and the character table of H q (w) in [BMa,5.A] that a representation is special if (and only if) the elements {(T i ) i=1,2,3 , (T i T j ) i=1,2,3, j=1+(i mod 3) , (Φ i ) i=1,2,3 } have trace zero on it. The quadratic relations show that B = {(T i ) i=1,2,3 , (T i Φ) i=1,2,3 , (Φ i ) i=1,2,3 } generates the same subspace of H q (w) as these elements.…”
Section: All S In the Support Of T Divide V On The Left And That In mentioning
confidence: 99%
“…It remains to see that the virtual representation i (−1) i H i c (X(c)) of H(c) is special. But, by e.g., [BMa,2.2], the symmetrizing trace on H(c) is characterized by its vanishing on T i for i = 1, . .…”
Section: §1 Introductionmentioning
confidence: 99%