2011
DOI: 10.1016/j.scriptamat.2011.09.028
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Enhanced thermal conductivity in copper matrix composites reinforced with titanium-coated diamond particles

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Cited by 217 publications
(72 citation statements)
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“…(ii) using multimodal diamond particle mixtures to increase the diamond content in the composite [5][6][7]; or (iii) engineering the matrix-diamond interface, either by forming a new reaction layer during processing [8][9][10][11] or using diamond particles previously treated with different coatings [12][13][14][15][16][17][18].…”
Section: Introductionmentioning
confidence: 99%
See 1 more Smart Citation
“…(ii) using multimodal diamond particle mixtures to increase the diamond content in the composite [5][6][7]; or (iii) engineering the matrix-diamond interface, either by forming a new reaction layer during processing [8][9][10][11] or using diamond particles previously treated with different coatings [12][13][14][15][16][17][18].…”
Section: Introductionmentioning
confidence: 99%
“…Two strategies were used. First, a surface coating of nano-dimensioned TiC was applied to the diamond particles (TiC coatings have been proven to enhance the metal-diamond interface thermal conductance for metals such as Al [12,13] and Cu [14][15][16]). Second, at the micro-/meso-scale, a proper design route based on blending different predictive models was used to select the most adequate combinations of bimodal diamond particle mixtures.…”
Section: Introductionmentioning
confidence: 99%
“…Oxygenated diamond samples have roughly thermal interface conductance with Al four times higher than hydrogen-treated samples [20]. Different metallic coatings have been used to effectively increase the interfacial thermal conductance [21][22][23]. While some of the progresses detailed above are ultimately positive, some authors have identified the need of enhancing the intrinsic thermal conductivity of the diamond as the most promising direction of progress [9].…”
Section: Introductionmentioning
confidence: 99%
“…We follow Zhang et al (2011) and take v p ¼ ffiffiffiffiffiffiffiffiffiffi B=q s p % 3000m/s (B is the bulk modulus). The internal energy is given approximately by the enthalpy (this is valid under constant pressure, constant density and zero velocity), u ¼ c s DT, consequently in the following results we will employ a maximum value h max ¼ q s c s v s % 4:4 Â 10 9 W/m 2 K.…”
Section: Newton Cooling At the Outer Boundarymentioning
confidence: 99%