Surveys in Combinatorics 2007 2007
DOI: 10.1017/cbo9780511666209.006
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Designs and topology

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Cited by 31 publications
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“…We also note that, as observed in , if the current graph is bipartite, then the embedding is face two‐colorable. In our case the vertices in the current graph in one partition will form the STS( n ) in the derived embedding and the vertices in the second partition the hamilton cycle decomposition of Kn.…”
Section: Introductionmentioning
confidence: 53%
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“…We also note that, as observed in , if the current graph is bipartite, then the embedding is face two‐colorable. In our case the vertices in the current graph in one partition will form the STS( n ) in the derived embedding and the vertices in the second partition the hamilton cycle decomposition of Kn.…”
Section: Introductionmentioning
confidence: 53%
“…In answering the first question we find a two‐colorable embedding of an STS( n ) with faces of the second color class as small as possible, while in answering the second question the face of the second color class. In this article we tackle an intermediate question (first asked in ): does there exist a biembedding of an STS( n ) in a nonorientable surface such that the faces of the second color class are as large as possible subject to the restriction that no vertex is repeated on the boundary of any face, that is, the boundaries of faces in the second color class form the hamilton cycles in a hamilton cycle decomposition of Kn? In this article we will show that, in the case where n3(mod36) and n>3, the answer is in the affirmative.…”
Section: Introductionmentioning
confidence: 99%
“…There is a well-studied connection between graph embeddings and combinatorial designs arising from the fact that when a graph is embedded in a surface, the faces can be regarded as blocks of a design. An excellent survey on graph embeddings and combinatorial designs can be found in [14]. A face 2-colorable circular embedding of the complete graph K k (in some surface) in which each face is a triangle is a biembedding of two Steiner triple systems of order k. Results relating to biembeddings of Steiner triple systems can be found in [5], [19], [20].…”
Section: Introductionmentioning
confidence: 99%
“…Face 2‐colorability requires z ≡1, 3, 7, 9 (mod 12) in the nonorientable case, and z ≡3, 7 (mod 12) in the orientable case. In the articles , (see also for a survey), the authors constructed a ·2 italicbz 2 nonisomorphic triangular embeddings of K z ( a and b being positive constants) in both the orientable and nonorientable cases, provided that z is sufficiently large and lies in certain congruence classes. For example, if z ≡7, 19 (mod 36), then it is shown in that, as z →∞, there are at least face 2‐colorable triangular embeddings of K z in an orientable surface.…”
Section: Introductionmentioning
confidence: 99%