“…Hence, with a complexity of 2 14 , we can determine the candidates of Q 0 = {m 7 , m 0 } satisfying (6). Similarly, we can determine Q 1 = {m 8 , m 7 }, Q 2 = {m 9 , m 8 }, Q 3 = {m 10 , m 9 }, Q 4 = {m 11 , m 10 }, Q 5 = {m 12 , m 11 }, Q 6 = {m 13 , m 12 }, Q 7 = {m 14 , m 13 } and Q 8 = {m 15 , m 14 } from (7).…”