2004
DOI: 10.1017/s0017089504001922
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Biembeddings of Latin Squares and Hamiltonian Decompositions

Abstract: Abstract. Face 2-colourable triangulations of complete tripartite graphs K n,n,n correspond to biembeddings of Latin squares. Up to isomorphism, we give all such embeddings for n = 3, 4, 5 and 6, and we summarize the corresponding results for n = 7. Closely related to these are Hamiltonian decompositions of complete bipartite directed graphs K * n,n , and we also give computational results for these in the cases n = 3, 4, 5 and 6.2000 Mathematics Subject Classification. 05B15, 05C10. Introduction.A number of r… Show more

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Cited by 23 publications
(56 citation statements)
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“…Furthermore, as proved in [5], the orientability of such a triangular embedding is equivalent to face 2-colourability. By selecting one of the three sets of the tripartition of K n,n,n , and by deleting these vertices and the edges incident with them, one may obtain from T n a regular Hamiltonian embedding of K n,n in an orientable surface.…”
mentioning
confidence: 80%
“…Furthermore, as proved in [5], the orientability of such a triangular embedding is equivalent to face 2-colourability. By selecting one of the three sets of the tripartition of K n,n,n , and by deleting these vertices and the edges incident with them, one may obtain from T n a regular Hamiltonian embedding of K n,n in an orientable surface.…”
mentioning
confidence: 80%
“…In the context of non-existence results, some small Latin squares do not appear in any biembeddings [5]. In [11], the present authors introduced the concept of the parity vector of a main class of Latin squares.…”
Section: Introductionmentioning
confidence: 99%
“…A triangular embedding of a complete regular tripartite graph K n,n,n in a surface is face two-colourable if and only if the surface is orientable [5]. In this case, the faces of each colour class can be regarded as the triples of a transversal design T D(3, n), of order n and block size 3.…”
Section: Introductionmentioning
confidence: 99%
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